Quick Tricks for Quantitative Aptitude Topics Asked in Government Exam: Quantitative aptitude is an important part of all major competitive exams. In most of the exam, aptitude test is conducted as a part of the written exam, which is usually the very first round of the selection procedure. Aptitude test basically involves mathematical questions. In these questions, speed of the candidate matters more than his/her knowledge.
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This article is based on Quick Tricks for Quantitative Aptitude topic asked in Government Exams. Below mentioned are some tips and tricks to improve your maths for your upcoming exam.
What are the Quick Tricks for Quantitative Aptitude
Quantitative Aptitude Tests evaluate numerical ability and problem solving skills of candidates. This test forms the major part of a number of important entrance exams for different fields.
In this section, we are going to discuss the one of the most important topic – “Percentage”. Let us discuss these tricks to efficiently handle “Percentage” topic.
To begin with, let us solve this basic question. You need to find as to which one is the higher of the following two –
a) 3% of 234
b) 234% of 3
Most of the students would say that the answer is 234% of 3. Before we give you an answer, let us understand the basics of “Percentage”
We write “%” as (1/100) and the meaning of “of” is ‘Product’ of the given values. Now,
- 3% of 234 = (3/100) X 234
- 234% of 3 = (234 /100) X 3
If you observe this carefully, you will come to understand that both of the above values are equal. This leads to a very important understanding – order does not matter if the values that are in the consideration are equal.
a % of b = b % of a
To begin with, let us solve the following problem –
Population of a village increases by 10% every year for two years in a row. By what percent, the population will increase effectively after two years?
Population at the end of the first year – 100 + 10% of 100 = 110Let us say that the population of the village is 100.
Population at the end of the second year – 110 + 10% of 110 = 121
Hence, the growth of the population in two years = ( ) x 100
= x 100 = 21 %
Hence the population increases effectively by 21 % after two years.
Now, let us introduce ‘ab’ formula. You should use it when the given value undergoes two successive changes.
Final % change after two successive percent changes ‘a’ and ‘b’ – a %+b% + %
Here in the given problem – a = 10%, b = 10%
Now, let us use this formula to solve the above mentioned problem
= 10 + 10 + ()
= 21% (Could you see that we have solved the problem in a single line. Is it not amazing)?
Now, you solve the problems given below by using these techniques and put your answers in the ‘comment tab’. First five students who answer all the problems correctly will get a mentoring call from our TyariGuru Amit. Do not miss this opportunity to be in the league of the winners by taking the right guidance. Hit the comment box right now –
Question 1 Population of a village increases by 10% in the first year and then decreases by 10 % in the second year. Is there a change in the population after two years? If yes then what is your answer?
Question 2 Which of the following is the highest among the followings?
- 10% of 24% of 23
- 12% of 46 % of 10
- 6 % of 5 % of 92
Question 3 The population of a village decreases by 20% in the first year. By what percent, should it increase in the second year so that there is no change in the population after two years?
You can engage in live Discussion in the comments section below. Tomorrow we will tell you the answers of the above mentioned questions. Till then give your answers for the above topics in the comments below.
Every Tuesday we will be publishing a blog on tips & tricks on how to improve you Math. Till then stay tuned with us…
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